| Run ID | Author | Problem | Lang | Verdict | Score | Time | Memory | Code Length | Submit Time |
|---|---|---|---|---|---|---|---|---|---|
| 250 | 徐杨奕 | 超市卖电池 | C++ | Wrong Answer | 0 | 0 MS | 248 KB | 176 | 2019-09-18 19:14:32 |
#include<iostream> int main(){ int a; float b; scanf("%d",&a); if(a>=10){ b=2*a*0.9; printf("%.1f",b); }else{ b=a*2; printf("%.1f",b); } return 0; }