| Run ID | Author | Problem | Lang | Verdict | Score | Time | Memory | Code Length | Submit Time |
|---|---|---|---|---|---|---|---|---|---|
| 1101 | 顾郁铭 | 编程求1+1/2+1/3+...+1/n | C++ | Accepted | 100 | 0 MS | 252 KB | 142 | 2019-10-01 20:35:30 |
#include<iostream> int main(){ float n,d; scanf("%f",&n); d=1; while(n>1){ d=d+1/n; n--; } printf("%.3f",d); return 0; }